1 |
|||||||||||||||||||
1 |
1 |
||||||||||||||||||
1 |
2 |
1 |
|||||||||||||||||
1 |
3 |
3 |
1 |
||||||||||||||||
1 |
4 |
6 |
4 |
1 |
|||||||||||||||
1 |
5 |
10 |
10 |
5 |
1 |
||||||||||||||
1 |
6 |
15 |
20 |
15 |
6 |
1 |
|||||||||||||
1 |
7 |
21 |
35 |
35 |
21 |
7 |
1 |
||||||||||||
1 |
8 |
28 |
56 |
70 |
56 |
28 |
8 |
1 |
|||||||||||
1 |
9 |
36 |
84 |
126 |
126 |
84 |
36 |
9 |
1 |
||||||||||
1 |
10 |
45 |
120 |
210 |
252 |
210 |
120 |
45 |
10 |
1 |
|||||||||
1 |
11 |
55 |
165 |
330 |
462 |
462 |
330 |
165 |
55 |
11 |
1 |
||||||||
1 |
12 |
66 |
220 |
495 |
792 |
924 |
792 |
495 |
220 |
66 |
12 |
1 |
|||||||
1 |
13 |
78 |
286 |
715 |
1287 |
1716 |
1716 |
1287 |
715 |
286 |
78 |
13 |
1 |
||||||
1 |
14 |
91 |
364 |
1001 |
2002 |
3003 |
3432 |
3003 |
2002 |
1001 |
364 |
91 |
14 |
1 |
|||||
1 |
15 |
105 |
455 |
1365 |
3003 |
5005 |
6435 |
6435 |
5005 |
3003 |
1365 |
455 |
105 |
15 |
1 |
||||
1 |
16 |
120 |
560 |
1820 |
4368 |
8008 |
11440 |
12870 |
11440 |
8008 |
4368 |
1820 |
560 |
120 |
16 |
1 |
|||
1 |
17 |
136 |
680 |
2380 |
6188 |
12376 |
19448 |
24310 |
24310 |
19448 |
12376 |
6188 |
2380 |
680 |
136 |
17 |
1 |
||
1 |
18 |
153 |
816 |
3060 |
8568 |
18564 |
31824 |
43758 |
48620 |
43758 |
31824 |
18564 |
8568 |
3060 |
816 |
153 |
18 |
1 |
|
1 |
19 |
171 |
969 |
3876 |
11628 |
27132 |
50388 |
75582 |
92378 |
92378 |
75582 |
50388 |
27132 |
11628 |
3876 |
969 |
171 |
19 |
1 |
If you want to expand (a + b)10, for example, go to the row that begins 1, 10
(it's the 11th row if you start counting at 1 and the 10th row if you start counting at 0). The terms
of the expansion will all be of the form apbq where p+q=10 and p and q are whole
numbers between 0 and 10. Line the terms up starting with a10b0 and decreasing
the power of a and increasing the power of b. The coeficients in the row are then in the proper order.
So,
(a + b)10 = 1a10b0 + 10 a9b1
+45 a8b2
+120 a7b3 + 210 a6b4
+252 a5b5 +210 a4b6
+120 a3b7 + 45 a2b8
+10 a1b9 +1 a0b10
Remember that anything raised to the zero power is 1.
Another application of these numbers is that they give the number of different ways you can choose
some of a collection of objects. If you have 11 objects and you want to choose 3 of them, go to the 11th row (start counting at 0)
and the 3rd position in, again starting to count at 0 and you see that there are 165 different ways to choose
3 items from a collection of 11. This brings us to Pascal.
In the mid-1600s, while Blaise Pascal was working on one of his mathematical
treatises, one of his friends, the Chavalier de Mere, began asking him questions about gambling odds such as:
"In eight throws of a die, a player is to attempt to throw a one, but after three unsuccessful trials, the game
is interrupted. How should he be indemnified?"
[3, pg 363] Pascal's work in this area eventually
led to the modern theory
of probability which has spawned the related area of statistics. Little did Pascal know where his work would lead.
Nevertheless, since at the core of investigations of chance is the need to count the number of different possibilities,
Pascal made use of the arithmetic triangle in his work. Because of the attention that work received,
the triangle began to be known in the west as Pascal's Triangle.
The triangle is also frequently displayed in a symmetric manner where
each row is centered as below. Numerous people have studied the patterns to be found in the numbers in Pascal's triangle.
(See for example
[4],[8],[9],[11] and [14].) In this paper we will discuss one approach to looking for patterns in generalized versions of the triangle.
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